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Plus and cross are the two tensor components of a general-relativistic plane wave in an oriented transverse screen. They are not individually basis invariant: rotating the screen mixes them through twice the rotation angle. The complex combination h+−ih×h_+-i h_\times packages this spin-two transformation and supplies the convention used for every harmonic and asymptotic waveform in the volume. This kinematic baseline does not include empirical limits on additional polarizations.

Helpful background. Einstein Equations supplies the field equations that reduce the vacuum spectrum to two tensors. Waves, Green Functions, and Geometric Optics supplies null propagation and the transverse screen. Gravitational Radiation and Waveforms supplies TT strain and tidal response. Tests of Gravity supplies the later theory/observation setting in which this GR baseline is compared with alternatives.

Let the wave propagate toward the observer along a declared unit spatial vector n\boldsymbol n. Choose orthonormal vectors (p,q)(\boldsymbol p,\boldsymbol q) perpendicular to n\boldsymbol n, with p×q=n\boldsymbol p\times\boldsymbol q=\boldsymbol n. Define

eij+=pipj−qiqj,eij×=piqj+qipj.e^+_{ij}=p_ip_j-q_iq_j, \qquad e^\times_{ij}=p_iq_j+q_ip_j.

They are symmetric, transverse, and traceless:

nieijA=0,δijeijA=0,eijAeB ij=2δAB.n^ie^A_{ij}=0, \qquad \delta^{ij}e^A_{ij}=0, \qquad e^A_{ij}e^{B\,ij}=2\delta^{AB}.

The TT strain is

hijTT=h+eij++h×eij×.h^{\mathrm{TT}}_{ij} =h_+e^+_{ij}+h_\times e^\times_{ij}.

For propagation along +z+z with p=ex\boldsymbol p=\boldsymbol e_x and q=ey\boldsymbol q=\boldsymbol e_y,

hijTT=(h+h×0h×−h+0000).h^{\mathrm{TT}}_{ij} =\begin{pmatrix} h_+&h_\times&0\\ h_\times&-h_+&0\\ 0&0&0 \end{pmatrix}.

The two amplitudes are independent functions of retarded time. They are components of one tensor field, not two coordinate-invariant scalar fields.

The TT construction and its observable tidal interpretation are derived in Flanagan and Hughes 2005, §2.1, pp. 7–8, and §3, pp. 13–17, PDF.

Introduce the unit complex dyad

mi=pi+iqi2,mimˉi=1,mimi=0.m^i=\frac{p^i+iq^i}{\sqrt2}, \qquad m^i\bar m_i=1, \qquad m^im_i=0.

Contracting with two conjugate dyads gives

h=hijTTmˉimˉj=h+−ih×.h=h^{\mathrm{TT}}_{ij}\bar m^i\bar m^j =h_+-i h_\times.

Now rotate the dyad phase,

mi↦eiψmi.m^i\mapsto e^{i\psi}m^i.

For the real screen vectors this means

p′=pcos⁡ψ−qsin⁡ψ,q′=psin⁡ψ+qcos⁡ψ.p'=p\cos\psi-q\sin\psi, \qquad q'=p\sin\psi+q\cos\psi.

This explicit basis change fixes the sign of ψ\psi; the opposite geometric rotation uses −ψ-\psi.

The tensor itself is unchanged, while its complex component transforms as

h↦e−2iψh.h\mapsto e^{-2i\psi}h.

Thus hh has spin weight −2-2. Expanding the phase gives the real component transformation

h+′=h+cos⁡2ψ−h×sin⁡2ψ,h×′=h+sin⁡2ψ+h×cos⁡2ψ.\begin{aligned} h'_+&=h_+\cos2\psi-h_\times\sin2\psi,\\ h'_\times&=h_+\sin2\psi+h_\times\cos2\psi. \end{aligned}

If a source uses the opposite dyad rotation or defines h++ih×h_++i h_\times, both signs change together. The physical tensor and curvature do not.

Linear, circular, and elliptical polarization

Section titled “Linear, circular, and elliptical polarization”

For a monochromatic component with site time dependence e−iωte^{-i\omega t}, let H+H_+ and H×H_\times be complex amplitudes. Their relative magnitude and phase determine the polarization ellipse:

  • equal phases give linear polarization after a suitable screen rotation;
  • equal magnitudes with relative phase ±π/2\pm\pi/2 give circular polarization;
  • the generic case is elliptical.

Handedness requires an orientation and viewing direction. Looking along n\boldsymbol n versus back toward the source reverses the visual sense of rotation. A sign attached to “right-handed” without that statement is incomplete.

A real waveform contains conjugate positive- and negative-frequency content. Helicity language is most transparent for one frequency sign; the real time series should not be mistaken for a single unconjugated complex metric.

The local electric curvature is

R0i0j=−12h¨ijTT.R_{0i0j}=-\frac12\ddot h^{\mathrm{TT}}_{ij}.

For initial transverse separation (x0,y0)(x_0,y_0), the long-wavelength response is

δx=12(h+x0+h×y0),δy=12(h×x0−h+y0).\delta x=\frac12(h_+x_0+h_\times y_0), \qquad \delta y=\frac12(h_\times x_0-h_+y_0).

Plus stretches one screen axis while compressing the other. Cross has the same pattern rotated by 45∘45^\circ. Since a screen rotation mixes the component names, the invariant statement is that the tidal matrix is transverse and trace free with two eigen-directions.

The figure applies these displacement equations to an initially circular ring. Compare the principal axes of the plus and cross patterns, then compare opposite signs of the same amplitude.

Plus deforms an initially circular ring along the horizontal and vertical screen axes, while cross deforms it along axes rotated by forty-five degrees; reversing the amplitude exchanges stretching and compression.

The two tensor patterns for a wave along +z+z, with p×q=ez\boldsymbol p\times\boldsymbol q=\boldsymbol e_z. Each ring follows x=(I+hTT/2)x0\boldsymbol x=(I+h^{\mathrm{TT}}/2)\boldsymbol x_0; the dashed circle is undeformed. The amplitudes hA=±h0h_A=\pm h_0 use h0=0.4h_0=0.4 only to exaggerate the linear response. Area is preserved to first order, not exactly at this illustrative amplitude. These are phase snapshots, not additional independent polarizations.

Field, frame, and detector are different objects

Section titled “Field, frame, and detector are different objects”

A detector channel is a contraction of the spacetime field with a response tensor and, at finite frequency, a transfer function. In the long-wavelength idealization,

s(t)=DijhijTT=F+h++F×h×.s(t)=D^{ij}h^{\mathrm{TT}}_{ij} =F_+h_++F_\times h_\times.

The antenna factors FA=DijeijAF_A=D^{ij}e^A_{ij} depend on detector geometry and sky convention. They are not new spacetime polarizations. In column-vector notation, the amplitudes and antenna factors both transform with the same orthogonal doubled-angle matrix RR: h′=Rh\boldsymbol h'=R\boldsymbol h and F′=RF\boldsymbol F'=R\boldsymbol F. Thus s=FThs=\boldsymbol F^{\mathsf T}\boldsymbol h is unchanged because RTR=1R^{\mathsf T}R=1.

Detector calibration, networks, likelihoods, and empirical polarization bounds belong to Gravitational-Wave Astronomy and Tests of Gravity. This page defines the field-side basis.

Calling plus and cross invariant observables. Their two-dimensional span is physical; their individual values depend on the oriented screen.

Forgetting the doubled angle. A rank-two trace-free tensor rotates with 2ψ2\psi, which is why the complex field has spin weight −2-2.

Confusing cross with a non-GR mode. Cross is the second tensor polarization of GR. Vector and scalar modes have different tidal matrices, not merely different screen angles.

1. Forty-five-degree rotation. Set ψ=π/4\psi=\pi/4 in the component transformation. What happens to a pure plus wave?

Solution

Since cos⁡(π/2)=0\cos(\pi/2)=0 and sin⁡(π/2)=1\sin(\pi/2)=1,

h+′=0,h×′=h+.h'_+=0,\qquad h'_\times=h_+.

Thus a pure plus component becomes a pure cross component in the rotated screen convention. The tensor and its tidal eigenvalues are unchanged; only the component labels have rotated.

2. Basis-independent norm. Show that hijTThTTij=2∣h∣2h^{\mathrm{TT}}_{ij}h_{\mathrm{TT}}^{ij}=2\lvert h\rvert^2 for real time-domain components.

Solution

Orthogonality of the polarization tensors gives

hijhij=2(h+2+h×2).h_{ij}h^{ij}=2(h_+^2+h_\times^2).

Meanwhile ∣h+−ih×∣2=h+2+h×2\lvert h_+-i h_\times\rvert^2=h_+^2+h_\times^2. The norm therefore has the stated form and is unchanged by the phase e−2iψe^{-2i\psi}.

This supplies an immediate normalization check when plus and cross modes are rotated between waveform frames.

  • Flanagan, Éanna É., and Scott A. Hughes. “The Basics of Gravitational Wave Theory.” New Journal of Physics 7 (2005): 204. DOI. Open PDF.