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Uniform Acceleration and Rindler Wedges

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An observer accelerating eternally along one fixed spatial direction, with constant nonzero proper acceleration, follows a hyperbola that approaches two null lines. With null coordinates U=T−XU=T-X and V=T+XV=T+X, the complete right-accelerated orbit can receive signals only from U<0U\lt0 and can send signals only into V>0V\gt0. Their intersection, U<0<VU\lt0\lt V, is the right Rindler wedge: the region of two-way communication on which the stationary Rindler chart lives. The orbit’s causal past and causal future separately extend beyond that wedge. Its horizons are observer-dependent causal boundaries, not curvature singularities or a global black-hole event horizon.

Required background. Special Relativity provides Minkowski causal geometry, four-vectors, and mass-shell kinematics; Relativistic Observers and Measurement provides observer rest spaces and invariant decompositions of measured quantities. Helpful background. Calculus and Linear Algebra provides multivariable differentiation, linear maps, inner products, and basis changes; Ordinary Differential Equations provides initial-value problems, linearization, and asymptotic solution methods.

For motion along XX, introduce rapidity ϑ\vartheta:

uμ=(cosh⁡ϑ,sinh⁡ϑ,0,0).u^\mu=(\cosh\vartheta,\sinh\vartheta,0,0).

Then

aμ=dϑdτ(sinh⁡ϑ,cosh⁡ϑ,0,0),α=∣dϑdτ∣.a^\mu=\frac{d\vartheta}{d\tau}(\sinh\vartheta,\cosh\vartheta,0,0), \qquad \alpha=\left|\frac{d\vartheta}{d\tau}\right|.

For signed constant acceleration a>0a\gt0, choose the inertial origin at the center of the hyperbola and let the observer be instantaneously at rest at (T,X)=(0,a−1)(T,X)=(0,a^{-1}). Then ϑ=aτ\vartheta=a\tau and

T(τ)=a−1sinh⁡(aτ),X(τ)=a−1cosh⁡(aτ).\boxed{T(\tau)=a^{-1}\sinh(a\tau), \qquad X(\tau)=a^{-1}\cosh(a\tau).}

Consequently X2−T2=a−2X^2-T^2=a^{-2} and dX/dT=tanh⁡(aτ)dX/dT=\tanh(a\tau). The worldline approaches X=∣T∣X=|T| but never reaches either null line at finite proper time. The same hyperbolic solution is derived with explicit factors of cc in Hughes 2024, Lecture 14, §14.1, printed pp. 110–111, Eqs. (14.1)–(14.5).

Introduce coordinates (η,ρ,y,z)(\eta,\rho,y,z) by

T=ρsinh⁡(aη),X=ρcosh⁡(aη),ρ>0.T=\rho\sinh(a\eta), \qquad X=\rho\cosh(a\eta), \qquad \rho\gt0.

This is the traditional extended-tetrad construction in Pauri and Vallisneri 2000, §4, printed pp. 6–7, Eqs. (10)–(12). Direct substitution gives

ds2=−(aρ)2dη2+dρ2+dy2+dz2.\boxed{ds^2=-(a\rho)^2d\eta^2+d\rho^2+dy^2+dz^2.}

Every fixed-ρ\rho curve is uniformly accelerated, but its proper acceleration is 1/ρ1/\rho, not the same constant for the entire congruence. Indeed, its proper time is dσ=aρ dηd\sigma=a\rho\,d\eta, so its normalized tangent and four-acceleration are

uμ=(cosh⁡aη,sinh⁡aη,0,0),Aμ=1ρ(sinh⁡aη,cosh⁡aη,0,0).u^\mu=(\cosh a\eta,\sinh a\eta,0,0), \qquad A^\mu=\frac1\rho(\sinh a\eta,\cosh a\eta,0,0).

Thus u2=−1u^2=-1, u⋅A=0u\mathbin{\cdot}A=0, and A2=ρ−2A^2=\rho^{-2}. The original observer is at ρ=1/a\rho=1/a, where η\eta equals its proper time. This spatial variation is exactly what permits the coordinate distances between neighboring observers to remain constant.

The null-coordinate form of the map is especially useful:

U=−ρe−aη,V=ρeaη.U=-\rho e^{-a\eta}, \qquad V=\rho e^{a\eta}.

It makes U<0<VU\lt0\lt V immediate. Equivalently, the inverse relations are

ρ=X2−T2,tanh⁡(aη)=TX.\rho=\sqrt{X^2-T^2}, \qquad \tanh(a\eta)=\frac{T}{X}.

They exist only when X>∣T∣X\gt|T|, the right Rindler wedge. At finite η\eta, the limit ρ→0\rho\to0 maps only to the origin U=V=0U=V=0. A generic point on the future horizon U=0U=0, V>0V\gt0 instead requires the correlated limit ρ→0\rho\to0, η→+∞\eta\to+\infty with ρeaη\rho e^{a\eta} fixed; a generic point on the past horizon V=0V=0, U<0U\lt0 requires η→−∞\eta\to-\infty with ρe−aη\rho e^{-a\eta} fixed. The Rindler metric degenerates in these limiting coordinates, but the inertial metric remains regular.

The null surfaces X=±TX=\pm T are horizons for the chosen uniformly accelerated worldlines: causal curves from parts of Minkowski spacetime cannot cross them in the required direction and still meet those worldlines. Yet inertial observers cross them uneventfully. Calling them acceleration or Rindler horizons preserves the distinction from the observer-independent event horizon assigned to an entire asymptotic spacetime in black-hole geometry. The chart, its flat metric, and this causal restriction are exhibited in Hughes 2024, Lecture 14, §14.5, printed pp. 117–119, Eqs. (14.37)–(14.45).

The four-wedge picture makes the restricted chart visible. Its boost generator is

χ=∂η=a(X∂T+T∂X).\chi=\partial_\eta =a\left(X\partial_T+T\partial_X\right).

Its time component is χT=aX\chi^T=aX, so it is future-directed in the right wedge and past-directed in the left. Inspect the null boundaries and the hyperbolic orbits: a fixed-ρ\rho observer remains in one lateral wedge, while the same global boost generator has opposite time orientation on the mirror orbit in the other lateral wedge.

The null lines divide Minkowski space into right, left, future, and past wedges. Constant-acceleration hyperbolae stay in the right or left wedge and approach the null horizons; the boost generator runs futureward on the right orbit and pastward on the left.

Null lines divide Minkowski space into four wedges; constant-acceleration hyperbolae approach the horizons. Arrows show the same boost generator futureward on the right and pastward on the left. Horizon names refer to the right-wedge observer; schematic, not to scale.

The Rindler lapse is N=aρN=a\rho. A fixed-ρ\rho clock accumulates

dσ=aρ dη.d\sigma=a\rho\,d\eta.

For a photon, stationarity conserves E=−pη\mathcal E=-p_\eta. The local observer has u=(aρ)−1∂ηu=(a\rho)^{-1}\partial_\eta, so the measured frequency is

ω(ρ)=−p⋅u=Eaρ.\omega(\rho)=-p\mathbin{\cdot}u=\frac{\mathcal E}{a\rho}.

Thus two Rindler observers receiving the same null ray measure

ω2ω1=ρ1ρ2.\frac{\omega_2}{\omega_1}=\frac{\rho_1}{\rho_2}.

Light received at larger ρ\rho is redshifted. No spacetime curvature is needed; the sender and receiver belong to different accelerated worldlines. The clock-rate and spectral-shift calculation in the shifted coordinate ρ=a−1+x\rho=a^{-1}+x is worked through in Gourgoulhon 2010, PDF slides 28–30.

For a radial light signal, the null metric gives dρ/dη=±aρd\rho/d\eta=\pm a\rho. A signal sent outward from ρ1\rho_1 to ρ2>ρ1\rho_2\gt\rho_1 takes coordinate time Δη=a−1ln⁡(ρ2/ρ1)\Delta\eta=a^{-1}\ln(\rho_2/\rho_1). Successive crests have the same coordinate separation at either end because the metric is stationary, but the local clock interval scales as aρa\rho. The larger interval at the receiver is the same redshift derived from the conserved photon energy.

  • For the inertial limit, write ρ=a−1+ξ\rho=a^{-1}+\xi and recenter X′=X−a−1X'=X-a^{-1}. At fixed (η,ξ)(\eta,\xi), a→0a\to0 gives T→ηT\to\eta, X′→ξX'\to\xi, and the metric tends to inertial form.
  • “Constant acceleration” must mean constant proper acceleration along one orbit. A Born-rigid Rindler family necessarily has α=1/ρ\alpha=1/\rho.
  • The Rindler construction also requires rectilinear acceleration. Uniform circular motion has constant proper-acceleration magnitude but does not follow these hyperbolae. A rocket that accelerates for a finite interval and then coasts forever has no future reception horizon of this type: an eventual timelike straight line can receive a signal from any fixed event in Minkowski spacetime if given enough time. Horizons depend on the complete history, not one accelerometer reading.
  • The Rindler chart covers neither the future and past wedges nor the left wedge. This is a chart and congruence choice, not missing spacetime.
  • A coordinate horizon can coincide with a causal horizon for specified observers without becoming a global event horizon or a curvature singularity.
  • The classical Rindler horizon does not by itself establish Unruh radiation; that conclusion requires quantum field theory and a state choice.

Transfer task: a finite accelerating rocket

Section titled “Transfer task: a finite accelerating rocket”

The rear of a rocket has proper acceleration a0a_0 and sits at ρ0=1/a0\rho_0=1/a_0. Its front is a proper distance L>0L\gt0 ahead on an η=constant\eta=\text{constant} slice. Find the front acceleration and its clock rate relative to the rear.

Solution

The front is at ρf=a0−1+L\rho_f=a_0^{-1}+L, so

af=1ρf=a01+a0L.\boxed{a_f=\frac{1}{\rho_f}=\frac{a_0}{1+a_0L}}.

At equal dηd\eta, proper times obey

dσfdσ0=aρfaρ0=1+a0L.\frac{d\sigma_f}{d\sigma_0} =\frac{a\rho_f}{a\rho_0} =1+a_0L.

The front accelerates less and its clock advances faster. For a0L≪1a_0L\ll1, the fractional differences are −a0L-a_0L in acceleration and +a0L+a_0L in clock rate. Assigning the same a0a_0 to every point would destroy the fixed-distance Rindler arrangement.

Continue to Rotating Frames, Sagnac Timing, and Light Cylinders, where a closed spatial loop makes the synchronization obstruction measurable.